Re: [xsl] accessing multiple xml documents from within one template

no, reportDef.xml is not output, but another input, the definition of
the resulting report. The output would be a list, in csv format it
would look like this:

Book title,# pages
Hamlet,120
The Perfume,230

Regards, Stefan

2009/1/16 Ganesh Babu N <nbabuganesh(_at_)gmail(_dot_)com>:

As per my understanding the input is books.xml  and output is reportDef.xml.

You have to write the templates matching books.xml and wrap the
content with the reporDef elements/attributes.

If you have multiple XML files as input you should use  collection() of xslt2

Regards,
Ganesh


On Fri, Jan 16, 2009 at 4:38 AM, Stefan Hunziker 
<stefan(_at_)stanjasele(_dot_)ch> wrote:

hi

In my main books.xml document being processed I have a number of
books, as follows:

<books>
       <book>
               <title>Hamlet</title>
               <author>Shakespeare</author>
               <publisher>Peares</publisher>
               <pagecount>120</pagecount>
               <weight>500g</weight>
       </book>
       <book>
               <title>The Perfume</title>
               <author>Sueskind</author>
               <publisher>ABC</publisher>
               <pagecount>230</pagecount>
               <weight>256g</weight>
       </book>
</books>

in a second reportDef.xml I want to define a report list, as follows:

<reportDef>
       <col title="Book title" field="title" type="text"/>
       <col title="# pages" field="pagecount" type="number"/>
</reportDef>


Now, with xsl I like to generate a report. Until now it looks like:

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
       <xsl:output  method="text" indent="no" encoding="ISO-8859-1"/>
       <xsl:variable name="reportDef" select="document('reportDef.xml')"/>

       <xsl:template match="books">
               <xsl:apply-templates select="$reportDef" mode="header"/>&#xA;
               <xsl:apply-templates select="book"/>
       </xsl:template>

       <xsl:template match="book">
               <xsl:apply-templates select="$reportDef" mode="data"/>&#xA;
       </xsl:template>

       <xsl:template match="col" mode="header">
               <xsl:value-of select="@title"/>; <!-- this one is no 
problem-->
       </xsl:template>

       <xsl:template match="col" mode="data">
               <xsl:variable name="fieldname" select="@field"/>;
               <!-- here I want to print the book property $fieldname, but I 
can't
access the main xml books -->
       </xsl:template>
</xsl:stylesheet>


The problem is, that I don't see the books.xml from within the
reportDef templates (<xsl:template match="col" mode="data">). Also
when I pass the book node by param to the template there is no content
in this node!

I would be very happy if anybody could give me a hint

Thanks very much
Stefan

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