Use *[name()=$fieldname], and if it's too slow then find a faster processor.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Stefan Hunziker [mailto:stefan(_dot_)stanjasele(_at_)gmail(_dot_)com]
Sent: 16 January 2009 23:01
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] accessing multiple xml documents from
within one template
I have a solution now for accessing both trees, I have to
step through the reportDef using xsl:for-each. But now I have
the next problem:
In $fieldname there is the desired tag, eg "title". Can I get
the title element of my current book node without looping
through the whole node and comparing with name(.)=$fieldname?
The given sample is a simplification, the real book node in
my application has maybe 100 elements and with maybe 1000
books this would be a little bit too time consuming.
any ideas?
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