In XSLT 2.0:
<xsl:template match="Catalog">
<xsl:result-document href="cds.xml">
<xsl:copy-of select="cds"/>
</xsl:result-document>
<xsl:result-document href="artists.xml">
<xsl:copy-of select="artists"/>
</xsl:result-document>
</xsl:template>
In XSLT 1.0, you need to write two separate transformations, one to produce
each output file.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Mike Stroud [mailto:stroudmw(_at_)gmail(_dot_)com]
Sent: 02 February 2009 11:56
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Using XSL to output 2 files
Hello All,
I have (another) question. I have an XML file that looks like this:
<?xml version="1.0" encoding="UTF-8"?>
<Catalog>
<cds>
<cd>
<number>000001</number>
<title>Empire Burlesque</title>
</cd>
<cd>
<number>000002</number>
<title>Hide Your Heart</title>
</cd>
</cds>
<artists>
<artist>
<number>000001</number>
<name>Bob Dylan</name>
</artist>
<artist>
<number>000002</number>
<name>Bonnie Tyler</name>
</artist>
</artists>
</Catalog>
Can I use XSL to output 2 files: 1 for cds and another for atrists?
<?xml version="1.0" encoding="UTF-8"?>
<cds>
<cd>
<number>000001</number>
<title>Empire Burlesque</title>
</cd>
<cd>
<number>000002</number>
<title>Hide Your Heart</title>
</cd>
</cds>
<?xml version="1.0" encoding="UTF-8"?>
<artists>
<artist>
<number>000001</number>
<name>Bob Dylan</name>
</artist>
<artist>
<number>000002</number>
<name>Bonnie Tyler</name>
</artist>
</artists>
Thanks, Mike.
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