[xsl] Decimal to hexadecimal in one function (XSLT/XPath 2)

Hi,

I want to convert the decimal integers returned by the XPath 2 function 
fn:string-to-codepoints into a sequence of strings that use the 
conventional "U+..." hexadecimal notation of the Unicode standard.
Neither the XPath 2 spec nor the XSLT FAQ offered a complete solution to 
this problem, so I developed my own. It is working, but I wonder how to 
integrate these two functions, which convert a decimal integer into its 
hexadecimal equivalent, into a single function which still returns just 
one string:
<xsl:function name="my:decimal-to-hex" as="xs:string">
  <xsl:param name="decimalNumber"/>
  <xsl:sequence 
select="string-join(my:decimal-to-hex-internal($decimalNumber),'')"/>
</xsl:function>

<xsl:function name="my:decimal-to-hex-internal" as="xs:string+">
  <xsl:param name="decimalNumber"/>
  <xsl:variable name="hexDigits" select="'0123456789ABCDEF'"/>
  <xsl:if test="$decimalNumber &gt;= 16">
    <xsl:sequence
      select="my:decimal-to-hex-internal(floor($decimalNumber div 16))"/>
  </xsl:if>
  <xsl:sequence
    select="substring($hexDigits, ($decimalNumber mod 16) + 1, 1)"/>
</xsl:function>


  Yves

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