Am 17.02.2009 um 12:22 schrieb Yves Forkl:
I want to convert the decimal integers returned by the XPath 2
function fn:string-to-codepoints into a sequence of strings that use
the conventional "U+..." hexadecimal notation of the Unicode standard.
Neither the XPath 2 spec nor the XSLT FAQ offered a complete
solution to this problem, so I developed my own. It is working, but
I wonder how to integrate these two functions, which convert a
decimal integer into its hexadecimal equivalent, into a single
function which still returns just one string:
<xsl:function name="my:decimal-to-hex" as="xs:string">
<xsl:param name="decimalNumber"/>
<xsl:sequence select="string-join(my:decimal-to-hex-
internal($decimalNumber),'')"/>
</xsl:function>
<xsl:function name="my:decimal-to-hex-internal" as="xs:string+">
<xsl:param name="decimalNumber"/>
<xsl:variable name="hexDigits" select="'0123456789ABCDEF'"/>
<xsl:if test="$decimalNumber >= 16">
<xsl:sequence
select="my:decimal-to-hex-internal(floor($decimalNumber div
16))"/>
</xsl:if>
<xsl:sequence
select="substring($hexDigits, ($decimalNumber mod 16) + 1, 1)"/>
</xsl:function>
I don't think it is elegant at all, but you can collect the recursive
digits in a variable and then do this:
<xsl:function name="my:decimal-to-hex" as="xs:string">
<xsl:param name="decimalNumber"/>
<xsl:variable name="hexDigits" select="'0123456789ABCDEF'"/>
<xsl:variable name="upperDigits">
<xsl:if test="$decimalNumber >= 16">
<xsl:sequence select="string-join(my:decimal-to-
hex(floor($decimalNumber div 16)), '')"/>
</xsl:if>
</xsl:variable>
<xsl:sequence select="string-join(($upperDigits,
substring($hexDigits, ($decimalNumber mod 16) + 1, 1)), '')"/>
</xsl:function>
- Michael
--
_______________________________________________________________
Michael Müller-Hillebrand: Dokumentations-Technologie
Adobe Certified Expert, FrameMaker
Lösungen und Training, FrameScript, XML/XSL, Unicode
Blog: http://cap-studio.de/ - Tel. +49 (9131) 28747
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