I've tried all sorts of methods and I just can't figure it out. I'm
wondering if I'm missing some fundamental understanding about how sort
works in xsl.
I've got a document that looks like this:
<projects>
<project active="1" published="1">stuff</project>
<project active="1" published="0">stuff</project>
<project active="0" published="1">stuff</project>
<project active="0" published="0">stuff</project>
</projects
And I need to be able to sort them (on the fly - it's part of a sortable
table in html) in this order and the reverse:
active, not published
active, published
not active, published
not active, not published.
I've tried all kinds of ways to sort them to get this to happen
including brute force:
<xsl:for-each select="project">
<xsl:sort select="@active=1 and @published=0"
order="ascending"
data-type="number"/>
<xsl:sort select="@active=1 and @published=1"
order="ascending"
data-type="number"/>
<xsl:sort select="@active=0 and @published=1"
order="ascending"
data-type="number"/>
<xsl:sort select="@active=0 and @published=0"
order="ascending"
data-type="number"/>
<xsl:copy-of select="."/>
</xsl:for-each>
Nothing works. It always comes out with at least one in the wrong spot.
Could someone point me in the right direction? Help me understand what
I'm missing about how sort works?
Thanks much in advance
Joelle
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--