Hey list,
to refresh an old thread again -- how can this be done in XSLT 1.0?
I don't need an exhaustive solution, just one that would cover the
most common URL syntax.
Martynas
www.xml.lt
On Wed, Aug 6, 2008 at 4:00 PM, Michael Kay <mike(_at_)saxonica(_dot_)com>
wrote:
You seem to be using XSLT 2.0 so this is definitely a case for regular
expressions.
I'm always a bit hesitant about pattern matching in the text - you have to
accept that there will be a proportion of wrong matches and that these will
irritate your users. (Microsoft Powerpoint seems to have a nasty habit of
highlighting XPath expressions and regular expressions as URL hyperlinks,
for example). So I think it's important (a) to be careful about it, and (b)
to be conservative.
A reasonable regex might be something like
\s(http://|www)(\.[a-z0-9])+\.(com|org|net|ca|uk|fr|de|...)[^\s]*
but I'm sure one could improve it.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Brent Solly [mailto:ultra(_at_)ymail(_dot_)com]
Sent: 06 August 2008 15:46
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Display link text as a hyperlink
I have an xml file that contains this character sequence:
'www.gamefaqs.com' .
Primary Problem:
After I convert the 'www' text to hyperlink format, the xsl
displays it as plain text, but I would like to display it has
a hyperlink.
Secondary:
I am aware that the url may also contain subfolders like:
www.gamefaqs.com/console/n64 OR different a suffix like
www.gamefaqs.ca., but right now I'll focus on .com, but feel
free to make suggestions :) .
<?xml version="1.0" encoding="UTF-8"?>
<rss>
<channel>
<item>
<description>More information on this game can be
found at (www.gamefaqs.com)</description>
</item>
</channel>
</rss>
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="2.0">
<xsl:strip-space elements="*" />
<xsl:output method="html" encoding="UTF-8"/>
<xsl:template name="globalReplace">
<xsl:param name="outputString"/>
<xsl:param name="target"/>
<xsl:param name="replacement"/>
<xsl:choose>
<!--Begin Test -->
<xsl:when test="contains($outputString,$target)">
<xsl:value-of select=
"concat(substring-before($outputString,$target),
$replacement)"/>
<xsl:call-template name="globalReplace">
<xsl:with-param name="outputString"
select="substring-after($outputString,$target)"/>
<xsl:with-param name="target" select="$target"/>
<xsl:with-param name="replacement"
select="$replacement"/>
</xsl:call-template>
</xsl:when>
<!--End Test-->
<xsl:otherwise>
<xsl:value-of select="$outputString"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template match="rss">
<xsl:call-template name="globalReplace">
<xsl:with-param name="outputString" select="."/>
<xsl:with-param name="target" select="'www'"/>
<xsl:with-param name="replacement" select="concat('<a
href="http://www',substring-before(substring-after(.,'www'
),substring-after(.,'com')),'">',substring-before(subst
ring-after(.,'www.'),'.com'),'</a>')"/>
</xsl:call-template>
</xsl:template>
</xsl:stylesheet>
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