Now I see that I over-simplified the problem. The XSLT also has to suppress
any <a1> that is not paired with an <a2>. So, I'm not sure the grouping works
in your example since there could be two <a1/> elements that are in the group
that ends with <a2/>. But, if you specify:
<xsl:for-each-group select="*"
group-starting-with="a1"
group-ending-with="a2">
will that consider "<a1/><a1/><a2/>" a group?
Dave
-----Original Message-----
From: Hintz, David L [mailto:david(_dot_)hintz(_at_)siemens(_dot_)com]
Sent: Thursday, April 23, 2009 1:36 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Need test for preceding-sibling
Thanks, Ken! I should have been clearer in my description. Each <a1> and <a2>
should be paired, even though there may be intervening tags. However, an <a2>
without its paired <a1> should not be processed. I'll try your grouping
solution.
Dave
-----Original Message-----
From: G. Ken Holman [mailto:gkholman(_at_)CraneSoftwrights(_dot_)com]
Sent: Thursday, April 23, 2009 1:26 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Need test for preceding-sibling
At 2009-04-23 14:01 -0400, Hintz, David L wrote:
I have a structure like this:
<a1/>
<a2/>
<a1/>
<a2/>
<b/>
<c/>
<a2/>
<a1/>
<a2/>
I need to ensure that each <a2> has a preceding <a1>, although there
may be intervening tags.
This description is a bit imprecise ... do you need them paired, or
will any <a1> before an <a2> suffice?
I ask because in the example you have every <a2> has a preceding
<a1>, some with intervening tags and some without.
But it isn't true that every <a2> has a preceding <a1> that follows
any preceding <a2>.
I know that
name(preceding-sibling::*[1]
gives me the name of the first preceding sibling, but how do I
construct a test that gives me only the first preceding <a1> or <a2> tag?
You shouldn't be working with name() because that deals with strings
and not expanded node names in a namespace-safe fashion.
The test that there is any <a1> before the current node being <a2> is:
preceding-sibling::a1
The test that there is an <a1> correspondingly before every <a2> is
approached more easily with XSLT 2 grouping from the parent of those siblings:
<xsl:for-each-group select="*"
group-ending-with="a2">
<xsl:if test="not(current-group()/self::a1)">
Error! No corresponding a1 for the given a2
</xsl:if>
</xsl:for-each-group>
I hope this helps.
. . . . . . . . . . . . Ken
--
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G. Ken Holman mailto:gkholman(_at_)CraneSoftwrights(_dot_)com
Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/
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