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RE: [xsl] HTML to XML

2009-05-27 12:36:51
Hi David and thx for the quick replied.

I'm a new user of this so I'm not sure that I should replied directly to
you bu t since I don't see the thread on the site I will, (until I know
better)

It work with this:
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xhtml="http://www.w3.org/1999/xhtml";>
<!--xsl:output method="text" indent="yes" encoding="UTF-8" /-->
<xsl:template match="xhtml:html">
        <xsl:value-of select="xhtml:head/xhtml:title" /> 
</xsl:template>
</xsl:stylesheet>
====================
But it's incredibly slow about 20-30 sec each, is that normal or there
something that I'm not doing properly.

My goal is to grab content from HTML page and render XML, I'm I on a
good path?

Thx for your time I will look to see if the Thread is there?

Michel
 

-----Original Message-----
From: David Carlisle [mailto:davidc(_at_)nag(_dot_)co(_dot_)uk] 
Sent: May 27, 2009 11:22 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Cc: Knight, Michel
Subject: Re: [xsl] HTML to XML


<xsl:template match="xhtml:html">
so there the current node is the html element

<html>
here you are making a node in the result tree that is html in
no-namespace ((perhaps that's what you want, or perhaps you want to add
xmlns="http://www.w3.org/199/xhtml";
to your xsl:stylesheet so that the result eleemnts are xhtmll.

        <!--xsl:value-of select="xhtml//head//title"/--> the first step
of that would select child elements of the current node that had name
xhtml in no namespace so <html xmlns="http://www.w3.org/199/xhtml";>
<xhtml xmlns="">

which is not there so it selects nothing.

Starting from the html element you want to step down two levels, the
child head element and its child title, both in the xhtml namespace so:

select="xhtml:head/xhtml:title"

David

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