An XSLT 1.0 solution:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:variable name="vrtfResults">
<r>1</r>
<r>1.70</r>
<r>2.25</r>
<r>3</r>
</xsl:variable>
<xsl:param name="optional.one" select="true()" />
<xsl:param name="optional.two" select="true()" />
<xsl:param name="optional.three" select="true()" />
<xsl:template match="/">
<xsl:variable name="vResults" select=
"document('')/*/xsl:variable[(_at_)name='vrtfResults']/*"
/>
<xsl:value-of select=
"$vResults[$optional.one
+ $optional.two
+ $optional.three
+ 1
]"/>
</xsl:template>
</xsl:stylesheet>
--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
---------------------------------------
To invent, you need a good imagination and a pile of junk
-------------------------------------
Never fight an inanimate object
-------------------------------------
You've achieved success in your field when you don't know whether what
you're doing is work or play
On Wed, Jun 10, 2009 at 2:20 PM, Karl Stubsjoen<kstubs(_at_)gmail(_dot_)com>
wrote:
I have 3 optional param values that are either true/false. I need a
solution which will return 4 different numbers when:
1) all param values are true
2) two param values are true
3) one param value is true
4) none are true
I was about to write one big choose and then thought maybe there is a
more efficient way of doing it. So any ideas on this one? For sake
of discussion, here is a mock up of the template and param values I
have:
<xsl:template name="test">
<xsl:param name="optional.one" select="true()" />
<xsl:param name="optional.two" select="true()" />
<xsl:param name="optional.three" select="true()" />
<!--
Return:
When All, return 3.00
When Two, return 2.25
When One, return 1.70
When Zero, return 1.00
-->
</xsl:template/>
Thanks for the help!
Karl..
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