Michael Kay wrote:
select="(1.0, 1.7, 2.25, 3.0)[count(($opt.one, $opt.two, $opt.three)[.])+1]"
The strange predicate [.] selects items in the sequence that are true.
Would someone expand on this oddity please?
I'm guessing 'true' in this case is the xslt version of 'true'...
I.e. non-empty?
How does that relate to
($opt.one, $opt.two, $opt.three)[.] please?
You make it look like a subscript into an array Mike?
regards DaveP
Regards,
Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay
-----Original Message-----
From: Karl Stubsjoen [mailto:kstubs(_at_)gmail(_dot_)com]
Sent: 10 June 2009 22:20
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] A smarter choose operation XSL 1.1
I have 3 optional param values that are either true/false. I
need a solution which will return 4 different numbers when:
1) all param values are true
2) two param values are true
3) one param value is true
4) none are true
I was about to write one big choose and then thought maybe
there is a more efficient way of doing it. So any ideas on
this one? For sake of discussion, here is a mock up of the
template and param values I
have:
<xsl:template name="test">
<xsl:param name="optional.one" select="true()" />
<xsl:param name="optional.two" select="true()" />
<xsl:param name="optional.three" select="true()" />
<!--
Return:
When All, return 3.00
When Two, return 2.25
When One, return 1.70
When Zero, return 1.00
-->
</xsl:template/>
Thanks for the help!
Karl..
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regards
--
Dave Pawson
XSLT XSL-FO FAQ.
http://www.dpawson.co.uk
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