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Re: [xsl] Keep track of visited path

2009-08-12 12:18:55
I am trying to navigate through a graph by going through every path between 
elements.
I face the problem of not being able to accumulate the visited paths(links 
between elements). The graph contain cycles, to avoid infinite loops (and 
stack overflow) i need to keep track of the visited path.


Has been done five years ago and is not difficult to do in XSLT 1.0,
See for example:

     http://lists.xml.org/archives/xml-dev/200401/msg00444.html


-- 
Cheers,
Dimitre Novatchev
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Truly great madness cannot be achieved without significant intelligence.
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To invent, you need a good imagination and a pile of junk
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Never fight an inanimate object
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You've achieved success in your field when you don't know whether what
you're doing is work or play
-------------------------------------
I enjoy the massacre of ads. This sentence will slaughter ads without
a messy bloodbath.




On Wed, Aug 12, 2009 at 8:21 AM, MMM FINE<mm1fine(_at_)yahoo(_dot_)com> wrote:

Hello Everybody,
I am trying to navigate through a graph by going through every path between 
elements.
I face the problem of not being able to accumulate the visited paths(links 
between elements). The graph contain cycles, to avoid infinite loops (and 
stack overflow) i need to keep track of the visited path.


I am using Altova XML Spy 2009 sp1, and XSLT 2.0


Any help is appreciated,


Waiting your responses :)




Simplified version of the source file:


<element id="abc-001" name="A">
<links>
<link id="link-001" start="abc-001" end="abc-002"/> <!--out link-->
</links>
</element>
<element id="abc-002" name="B">
<links>
<link id="link-001" start="abc-001" end="abc-002"/><!--in link-->
<link id="link-002" start="abc-002" end="abc-003"/><!--out link-->
</links>
</element>
<element id="abc-003" name="C">
<links>
<link id="link-002" start="abc-002" end="abc-003"/><!--in link-->
<link id="link-003" start="abc-003" end="abc-004"/><!--out link-->
<link id="link-004" start="abc-003" end="abc-005"/><!--out link-->
<link id="link-005" start="abc-003" end="abc-006"/><!--out link-->
</links>
</element>
<element id="abc-004" name="D">
<links>
<link id="link-003" start="abc-003" end="abc-004"/><!--in link-->
<link id="link-006" start="abc-004" end="abc-007"/><!--out link-->
</links>
</element>
<element id="abc-005" name="E">
<links>
<link id="link-004" start="abc-003" end="abc-005"/><!--in link-->
<link id="link-010" start="abc-005" end="abc-010"/><!--out link-->
<link id="link-011" start="abc-005" end="abc-011"/><!--out link-->
<link id="link-012" start="abc-005" end="abc-012"/><!--out link-->
<link id="link-013" start="abc-005" end="abc-013"/><!--out link-->
<link id="link-014" start="abc-005" end="abc-014"/><!--out link-->
</links>
</element>
<element id="abc-006" name="F">
<links>
<link id="link-005" start="abc-003" end="abc-006"/><!--in link-->
<link id="link-008" start="abc-006" end="abc-008"/><!--out link-->
<link id="link-009" start="abc-006" end="abc-009"/><!--out link-->
<link id="link-015" start="abc-006" end="abc-010"/><!--out link-->
<link id="link-016" start="abc-006" end="abc-011"/><!--out link-->
</links>
</element>
<element id="abc-007" name="G">
<links>
<link id="link-006" start="abc-004" end="abc-007"/><!--in link-->
</links>
</element>








The desired output :
Starting with A :
link-001 →
link-001 link-002 →
link-001 link-002 link-003 link-004 link-005 →
link-001 link-002 link-003 link-004 link-005 link-006 →
link-001 link-002 link-003 link-004 link-005 link-006 link-007→
link-001 link-002 link-003 link-004 link-005 link-006 link-007 link-010 
link-011 link-012 link-013 link-014 →
link-001 link-002 link-003 link-004 link-005 link-006 link-007 link-010 
link-011 link-012 link-013 link-014 link-008 link-009 link-015 link-016




Current XSLT Stylesheet:


<xsl:template name="followLink">
<xsl:param name="sortedLinks" as="node()+"/>
<xsl:param name="oldLinks" as="xs:string" select="''"/>

<xsl:variable name="visitedLinks" select="doc:visitedLinks($sortedLinks, 
$oldLinks)"/>
<xsl:for-each select="$sortedLinks">
<!--elementNode contains the current element-->
<xsl:variable name="elementNode" select="key('elemKey',./@end)"/>
<xsl:choose>
<xsl:when test="count( $elementNode/links/link[(@start = ../../@id) and 
(@start != @end) ] ) > 0">
<xsl:choose>
<!--number of outlinks and not self referenced = 1 -->
<xsl:when test="count( $elementNode/links/link[(@start = ../../@xmi:idref) 
and (@start != @end) ] ) = 1">
<xsl:call-template name="followLink">
<xsl:with-param name="sortedLinks" 
select="$elementNode/links/link[(_at_)start = ../../@id]"/>
<xsl:with-param name="oldLinks" select="$visitedLinks"/>
</xsl:call-template>
</xsl:when>
<!-- number of outlinks and not self referenced > 1 -->
<xsl:otherwise>
<!--Sort links according to some criteria-->
<xsl:call-template name="followLink">
<xsl:with-param name="sortedLinks" select="$sortedLinks"/>
<xsl:with-param name="oldLinks" select="$visitedLinks"/>
</xsl:call-template>
</xsl:otherwise>
</xsl:choose>
</xsl:when>
<xsl:otherwise/>
</xsl:choose>
</xsl:for-each>
</xsl:template>


<xsl:function name="doc:visitedLinks" as="xs:string*">
<xsl:param name="sortedLinks" as="node()+"/>
<xsl:param name="oldLinks" as="xs:string+"/>

<xsl:variable name="visitedLinks" as="xs:string+">
<xsl:for-each select="$sortedLinks">
<xsl:sequence select="concat($delimiter, ./@id, $delimiter)"/>
</xsl:for-each>
</xsl:variable>
<xsl:sequence select="string-join(($oldLinks, $visitedLinks), ' ')"/>
</xsl:function>


The current output is like this:
If i output the visited links at each iteration i get this:


link-001 →

link-001 link-002 →

link-001 link-002 link-003 link-004 link-005 →

link-001 link-002 link-003 link-004 link-005 link-006 →

link-001 link-002 link-003 link-004 link-005 link-006 link-007→

link-001 link-002 link-003 link-004 link-005 link-010 link-011 link-012 
link-013 link-014 →

link-001 link-002 link-003 link-004 link-005 link-008 link-009 link-015 
link-016


How can i write the doc:visitedLinks functions so it can return the result of 
for-each loop after each iteration?


Many thanks in advance,

Mike










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