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Re: [xsl] Re: adding column number to the entry

2009-09-04 09:52:53
Hi Ganesh,

The template provided does exactly transform the input provided to the
sample output provided.

The fact that you are introducing new constraints only shows that your
problem is not clearly expressed.

There may be other ways to track the index from the content and the
relationship between the entries could also be different.

As everything could change, it is difficult for me to justify the time
to address all possibilities.

As Tommie pointed out,

 1. provide the smallest possible example that illustrates your
    question. (it looks to me like there is a lot of "clutter" in
    your example; for example cell names and columnspans are not
    needed to deal with the question you asked)

 2. in addition to a small example describe in words, where the
    information in the desired result would come from in the
    input. Is it the case that you want RowSpan to equal 1
    unless the value of the cell element is longer than 16
    characters? Or is there some other logic that you want
    implemented in your XSLT?

Note that expressing the problem clearly may itself provide you with a
solution path.

I'll pass to someone else for now.

Cheers,
ac


That is only sample text (Table 1 TB...). In the real life that is not
possible.

I need to provide the sequence number of entries in that row and give
the number in the name attribute. name=1 for the first entry and
name=2 to the second entry etc. When morerows=1 means when rowspan is
there the entries in the next row should get incremented from the
entry position in the previous row.


look at the input and generate the output given.

Thanks are regards,
Ganesh




On Thu, Sep 3, 2009 at 5:47 PM, ac<ac(_at_)hyperbase(_dot_)com> wrote:
Hi,

I may be missing something, but how about something along the lines of:

  <xsl:template match="entry">
      <cell Name="{substring(substring-after(., 'Table 1 TB C'), 1,
1)}" RowSpan="{if (xs:integer(@morerows)) then @morerows + 1 else 1}"
ColumnSpan="1">
          <xsl:value-of select="."/>
      </cell>
  </xsl:template>

Cheers,
ac



Please help me on this issue.

Regards,
Ganesh


On Tue, Sep 1, 2009 at 3:09 PM, Ganesh Babu N<nbabuganesh(_at_)gmail(_dot_)com>
wrote:

Dear All,

I am having a input like this.

<table>
      <row>
              <entry align="left" valign="top">Table 1 TB C1 R5</entry>
              <entry align="left" valign="top" morerows="1">Table 1 TB C2
R5 and
TB C2 R6 are merged</entry>
              <entry align="left" valign="top">Table 1 TB C3 R5</entry>
              <entry align="left" valign="top">Table 1 TB C4 R5</entry>
      </row>
      <row>
              <entry align="left" valign="top">Table 1 TB C1 R6</entry>
              <entry align="left" valign="top">Table 1 TB C3 R6</entry>
              <entry align="left" valign="top">Table 1 TB C4 R6</entry>
      </row>
</table>

My required output is as follows:

<table>
 <cell Name="1" RowSpan="1" ColumnSpan="1">Table 1 TB C1 R5</cell>
 <cell Name="2" RowSpan="2" ColumnSpan="1">Table 1 TB C2 R5 and TB
C2 R6 are merged</cell>
 <cell Name="3" RowSpan="1" ColumnSpan="1">Table 1 TB C3 R5</cell>
 <cell Name="4" RowSpan="1" ColumnSpan="1">Table 1 TB C4 R5</cell>
 <cell Name="1" RowSpan="1" ColumnSpan="1">Table 1 TB C1 R6</cell>
 <cell Name="3" RowSpan="1" ColumnSpan="1">Table 1 TB C3 R6</cell>
 <cell Name="4" RowSpan="1" ColumnSpan="1">Table 1 TB C4 R6</cell>
</table>

I have tried with the following code but it is changing the number in
all the 2nd row entries. It requires to be changed only in C3 of R6
and C4 of R6. Because C2 of R6 is already merged with C2 of R5.

<xsl:template match="entry>
    <xsl:if test="parent::row/preceding-sibling::row/entry/@morerows">
         <xsl:value-of select="position() +
parent::row/preceding-sibling::row/entry[(_at_)morerows]/position()"/>
    </xsl:if>
</xsl:template>

Please help me getting required output.

Regards,
Ganesh


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