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Re: [xsl] xsl-for-each-group in xslt 2.0

2009-09-28 11:01:32
2009/9/28 a kusa <akusa8(_at_)gmail(_dot_)com>:
Hi

I am having difficulties implementing xsl-for-each-group in xslt 2.0

My XML is as follows:

<list1>
<listitem>A</listitem>
<listitem>B</listitem>
<list2>
<listitem>C</listitem>
<listitem>D</listitem>
</list2>
</list1>

Every <listX><listitem> combination corresponds to one step.

So I want this to transform into:

<step1>A B</step1>
<step2>C D</step2>

I tried

<xsl template match="list1">

<xsl:-for-each-group select="." group-by="listitem">
<step1><xsl:apply-templates/></step1>

</xsl:for-each-group>
<xsl:template>

Can someone please help me understand where i am going wrong here?

It's not actually a grouping problem, the following templates will
give the output you want:

<xsl:template match="list1">
  <step1>
    <xsl:value-of select="listitem"/>
  </step1>
  <xsl:apply-templates select="list2"/>
</xsl:template>

<xsl:template match="list2">
  <step2>
    <xsl:value-of select="listitem"/>
  </step2>
  <xsl:apply-templates select="list3"/>
</xsl:template>

If the nesting depth is unknown you can modify that to be a single
template with name tests...


-- 
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/

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