a kusa wrote:
My XML is as follows:
<list1>
<listitem>A</listitem>
<listitem>B</listitem>
<list2>
<listitem>C</listitem>
<listitem>D</listitem>
</list2>
</list1>
Every <listX><listitem> combination corresponds to one step.
So I want this to transform into:
<step1>A B</step1>
<step2>C D</step2>
I am not sure you need xsl:for-each-group, for the above input (wrapped
in a root element) the following stylesheet creates above output
(wrapped in a root element):
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0">
<xsl:output indent="yes"/>
<xsl:template match="root">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[matches(local-name(), 'list[0-9]+')]">
<xsl:element name="step{substring-after(local-name(), 'list')}">
<xsl:value-of select="listitem"/>
</xsl:element>
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="text()"/>
</xsl:stylesheet>
--
Martin Honnen
http://msmvps.com/blogs/martin_honnen/
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