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Re: [xsl] reading files from directory and returning the same name to output directory

2009-11-30 10:16:13
Thank you very much Andrew. This is a pretty cool tool and works great!

On Mon, Nov 30, 2009 at 9:05 AM, Andrew Welch 
<andrew(_dot_)j(_dot_)welch(_at_)gmail(_dot_)com> wrote:
2009/11/30 a kusa <akusa8(_at_)gmail(_dot_)com>:
Hi

Here is my requirement.

Read XML files from an input directory.
The results must be in another output directory. But the names of the
result xml files must be the same as the input xml files.

How do I do this with XSLT 2.0?

You could:

- use the directory tab of Kernow (http://kernowforsaxon.sf.net/)
- or you could use Saxon directly from the command line
- or you could write a standalone transform that uses the collection()
function and xsl:result-document.




--
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/

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