xsl-list
[Top] [All Lists]

Re: [xsl] reading files from directory and returning the same name to output directory

2009-11-30 10:29:22
2009/11/30 a kusa <akusa8(_at_)gmail(_dot_)com>:
Hi

Here is my requirement.

Read XML files from an input directory.
The results must be in another output directory. But the names of the
result xml files must be the same as the input xml files.

How do I do this with XSLT 2.0?


If you are a Maven user you could use the Maven XSLT plugin
(http://mojo.codehaus.org/xslt-maven-plugin/transform-mojo.html) that
works in a batch mode as per your requirement.

Regards,

Michael
www.xml-solutions.com

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--