Re: [xsl] Format Phone number

yes there is a issue with even this approach.
I am using XSL 1.0
1.

<xsl:decimal-format name="phonenumber" decimal-separator="-" 
grouping-separator="&#x2011;"/>
<xsl:template match="/">
<xsl:value-of select='format-number(1234567890 div 10000, "#&#x2011;###-####", 
"phonenumber")' />
</xsl:template>


its returning 123-456-789 which is wrong. (Zero is missing)

2.
<xsl:decimal-format name="staff" grouping-separator="-"/>

  <xsl:value-of select='format-number(9058957869, "000-000-0000", 
"staff")'/>
its returning me 90-5895-7869 which is wrong.

required out put is 905-895-7869

Please suggest me the correct approach.

Thanks,
Anil
Michael Kay wrote:

> > thanks for your response. this is returing me  xx-xxxx-xxxx 
> > format not xxx-xxx-xxxx.
> > what could be the issue.
> >     
> That looks like a bug in your XSLT processor.
>
> (But this is not the way I would recommend tackling this problem).
>
> Regards,
>
> Michael Kay
> http://www.saxonica.com/
> http://twitter.com/michaelhkay 
>
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