group-starting-with="abs" would solve the problem for this example, but I've
no idea if it solves the general problem.
Regards,
Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay
-----Original Message-----
From: gregor FELLENZ [mailto:gregor(_at_)netzfrei(_dot_)org]
Sent: 16 March 2010 14:42
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] xsl-grouping two different elements together
hey all,
i've got another grouping problem. i'm a little stuck where
to look for.
given the following structure:
<?xml version="1.0" encoding="UTF-8"?>
<kapitel>
<abs>first</abs>
<einschub1>first_ein</einschub1>
<einschub1>second_ein</einschub1>
<leerzeile/>
<einschub1>third_ein</einschub1>
<abs>second</abs>
<einschub2>first_ein2</einschub2>
<abs>end</abs>
</kapitel>
this should transform to:
<?xml version="1.0" encoding="UTF-8"?>
<kapitel>
<abs>first</abs>
<einschub typ="1">
<abs>first_ein</abs>
<abs>second_ein</abs>
<leerzeile/>
<abs>third_ein</abs>
</einschub>
<abs>second</abs>
<einschub typ="2">
<abs>first_ein2</abs>
</einschub>
<abs>end</abs>
</kapitel>
my current xslt is:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xs="http://www.w3.org/2001/XMLSchema";
exclude-result-prefixes="xs" version="2.0">
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="kapitel">
<xsl:element name="kapitel">
<xsl:for-each-group select="*"
group-adjacent="local-name()" >
<xsl:choose>
<xsl:when
test="starts-with(current-grouping-key(),'einschub')">
<xsl:element name="einschub">
<xsl:attribute name="typ" select='replace(local-name(),
"[^\d]+", "")'/>
<xsl:apply-templates select="current-group()"/>
</xsl:element>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="current-group()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each-group>
</xsl:element>
</xsl:template>
<xsl:template match="einschub1|einschub2">
<xsl:element name="abs">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
but this creates two <einschub typ="1"> container. this makes
absolutely sense, but i've no idea how to get the <leerzeile>
element into the container.
my only idea is to make a 2 pass solution:
1. rename all <leerzeile> elements with a template ...
<xsl:when
test="preceding-sibling::*[1][starts-with(local-name(),'einsch
ub')] and
following-sibling::*[1][starts-with(local-name(),'einschub')]
"> <xsl:element name="{local-name(preceding-sibling::*[1])}"> ...
2. grouping works.
is there any better/more elegant solution? or ideas where to look for?
thanks in advance,
regards,
gregor
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