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Re: [xsl] xsl-grouping two different elements together

2010-03-16 11:37:38
hi david,

thanks a lot, this works.

gregor

On 16.03.2010 17:21, David Carlisle wrote:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xs="http://www.w3.org/2001/XMLSchema"; exclude-result-prefixes="xs"
version="2.0">

<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="kapitel">
<xsl:copy>
<xsl:for-each-group select="*"
group-adjacent="string(following-sibling::*[starts-with(name(),'einschub')][1]/name())

= string(preceding-sibling::*[starts-with(name(),'einschub')][1]/name())
or starts-with(name(),'einschub')" >
<xsl:choose>
<xsl:when test="current-grouping-key()">
<einschub
typ="{current-group()[starts-with(name(),'einschub')][1]/substring-after(name(),'einschub')}">

<xsl:copy-of select="current-group()"/>
</einschub>
</xsl:when>
<xsl:otherwise>
<xsl:copy-of select="current-group()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each-group>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

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