Thx for your response.
I think grouping is important here because the 4th argument is the string that
should be replaced with.
In this argument are references to regex-groups...i'm not sure about that but i
think so.
If i remove the (?: the group numbers will change won't they ?!
regards
Patrick Szabo
XSLT-Entwickler
Tel.: +43 (1) 534 52 - 1573
Fax: +43 (1) 534 52 - 146
Patrick(_dot_)Szabo(_at_)lexisnexis(_dot_)at
LexisNexis Verlag ARD Orac GmbH & Co KG
Marxergasse 25, 1030 Wien
FN 8333f, Handelsgericht Wien
http://www.lexisnexis.at/
-----Ursprüngliche Nachricht-----
Von: Wolfgang Laun [mailto:wolfgang(_dot_)laun(_at_)gmail(_dot_)com]
Gesendet: Mittwoch, 14. April 2010 10:48
An: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Betreff: Re: [xsl] EXSLT replace to XSLT 2.0 replace
Omit the 'g', which replace() does anyway.
Omit the '(?: ... )" from the regular expression. (This is uncounted
grouping, which isn't important here.
The | in (\p{Lu}|\p{Ll}] looks suspicious. These are alternatives,
anyway, within []
-W
On Wed, Apr 14, 2010 at 9:48 AM, Szabo, Patrick (LNG-VIE)
<patrick(_dot_)szabo(_at_)lexisnexis(_dot_)at> wrote:
Hi,
I'm using Saxon 9 and XSLT 2.0
I'm currently updateing a few 1.0 Stylesheets to 2.0.
In one of those Stylesheets i've found this:
<xsl:value-of select="regexp:replace(.,
'(?:((_dot_)+(_at_)(_dot_)+\(_dot_)[a-zA-Z]+)|([\p{Lu}|\p{Ll}]\p{Ll}+)-([\p{Ll}]+))',
'g',
'$1$2$3')"/>
Is there a way to to that in 2.0 without EXSLT ?!
I - of course - wanted to try it with replace() but i cant seem to
figure it out.
best regards...
Patrick Szabo
XSLT-Entwickler
Tel.: +43 (1) 534 52 - 1573
Fax: +43 (1) 534 52 - 146
Patrick(_dot_)Szabo(_at_)lexisnexis(_dot_)at
LexisNexis Verlag ARD Orac GmbH & Co KG
Marxergasse 25, 1030 Wien
FN 8333f, Handelsgericht Wien
http://www.lexisnexis.at/
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