Dear Patrick,
in addition to what Wolfgang said:
- There is an undocumented feature in Saxon that will allow you to
preserve the passive group (?: ... ):
http://www.biglist.com/lists/lists.mulberrytech.com/xsl-list/archives/201002/msg00365.html
- If you change (?: ... ) to ordinary groups, you'll have to increment
the backreference numbers to '$2$3$4'
So either:
<xsl:value-of select="replace(
.,
'(?:((_dot_)+(_at_)(_dot_)+\(_dot_)[a-zA-Z]+)|([\p{Lu}|\p{Ll}]\p{Ll}+)-([\p{Ll}]+))',
'$1$2$3',
'!'
)"/>
or:
<xsl:value-of select="replace(
.,
'(((_dot_)+(_at_)(_dot_)+\(_dot_)[a-zA-Z]+)|([\p{Lu}|\p{Ll}]\p{Ll}+)-([\p{Ll}]+))',
'$2$3$4'
)"/>
Gerrit
On 14.04.2010 10:48, Wolfgang Laun wrote:
Omit the 'g', which replace() does anyway.
Omit the '(?: ... )" from the regular expression. (This is uncounted
grouping, which isn't important here.
The | in (\p{Lu}|\p{Ll}] looks suspicious. These are alternatives,
anyway, within []
-W
On Wed, Apr 14, 2010 at 9:48 AM, Szabo, Patrick (LNG-VIE)
<patrick(_dot_)szabo(_at_)lexisnexis(_dot_)at> wrote:
Hi,
I'm using Saxon 9 and XSLT 2.0
I'm currently updateing a few 1.0 Stylesheets to 2.0.
In one of those Stylesheets i've found this:
<xsl:value-of select="regexp:replace(.,
'(?:((_dot_)+(_at_)(_dot_)+\(_dot_)[a-zA-Z]+)|([\p{Lu}|\p{Ll}]\p{Ll}+)-([\p{Ll}]+))',
'g',
'$1$2$3')"/>
Is there a way to to that in 2.0 without EXSLT ?!
I - of course - wanted to try it with replace() but i cant seem to
figure it out.
best regards...
Patrick Szabo
XSLT-Entwickler
Tel.: +43 (1) 534 52 - 1573
Fax: +43 (1) 534 52 - 146
Patrick(_dot_)Szabo(_at_)lexisnexis(_dot_)at
LexisNexis Verlag ARD Orac GmbH& Co KG
Marxergasse 25, 1030 Wien
FN 8333f, Handelsgericht Wien
http://www.lexisnexis.at/
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