Variables in XSLT represent values, not fragments of expression text. It's
not a macro language. You can use the variable $name anywhere you would use
a string literal, for example
select="//x/*[local-name() = $name]/description"
Take care with namespaces.
Regards,
Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay
-----Original Message-----
From: Jacobus Reyneke [mailto:jacobusreyneke(_at_)gmail(_dot_)com]
Sent: 23 April 2010 14:09
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Required item type of first operand of '/' is
node(); supplied value has item type xs:string
Good day,
I have found a million references to this problem on the
Internet, but I still can't get my template to work. People
are typically experiencing these issues in functions and
parameter passing. My application is very simple, but the
solution keeps avoiding me.
I'm trying to use an element name as part of a path to a
central dictionary for my problem domain's terms. I'm keeping
the vocabulary under a different namespace so that I can move
it out later.
The following template:
<xsl:template match="c:*">
<xsl:variable name="name" select="local-name()"/>
<xsl:apply-templates
select="//c:smart-lookup-list/$name/description/node()"/>
</xsl:template>
Is not working and gives the error described above.
If I hardcode a value (lets say 'monkey') then off course it works:
<xsl:template match="c:*">
<xsl:variable name="name" select="local-name()"/>
<xsl:apply-templates
select="//c:smart-lookup-list/monkey/description/node()"/>
</xsl:template>
I'll be grateful for any guidance.
Kind regards,
Jacobus
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