I need to access the filename (well, actually without the extension, but that's
a simple RegEx) in an XSL Transform
Obviously, I can pass a xsl:param name= to a XSLT transform that contains the
filename, but I can't see how to achieve this when using Saxon's -s: command
line option where -s: contains a directory and not a file.
I'm sure there's got to be a way to find out the XML doc name that's being
transformed, but I just can't find it.
Is this possible?
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--