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Re: [xsl] Iteration of for() for first 100 intergers.

2010-11-18 10:32:09
For XSLT 1.0, you could use a recursive template, though some might
say that violates your "simple" requirement. :)

<xsl:call-template name="one-hundred"/>

<xsl:template name="one-hundred">
    <xsl:param name="i" select="0"/><!-- 0 is the default/starting value -->
    <xsl:if test="$i &lt;= 100">
        <xsl:value-of select="concat('each value ', $i,
'&#10;')"/><!-- linefeed after each value -->
        <xsl:call-template name="one-hundred"><!-- recurse, rather
than iterate, to next value -->
            <xsl:with-param name="i" select="$i + 1"/>
        </xsl:call-template>
    </xsl:if>
</xsl:template>

-Brandon :)


On Thu, Nov 18, 2010 at 11:09 AM, ram <ram_kurra(_at_)yahoo(_dot_)co(_dot_)in> 
wrote:
Hi,
  I am looking for simple for() which will iterate through first 100 numbers. 
  how can i do that.

for(int i=0;i<=100;i++){
  System.out.println("each value"+i);
}




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