My guess is that your stylesheet is going through the built-in
template rules, which do not pass simply-passed parameter values
down. What you have coded only works if the template being invoked
is invoked without the built-in template rules having been invoked in-between.
Note, however, that XSLT 2 supports tunnel parameters, which can be
considered to be automatically passed through every
<xsl:apply-templates> and every <xsl:call-template>, including
built-in template rules, without having to say so explicitly.
So, if you are running XSLT 2, try:
<xsl:with-param name="group-value" tunnel="yes" select="16"/>
... and the corresponding:
<xsl:param name="group-value" tunnel="yes" select="0"/>
BTW, you should note that:
select="number(16)"
... is redundant because just "16" is also interpreted as a number, and that
<xsl:param name="group-value">0</xsl:param>
... creates a variable of the type document tree with a root node and
a text node with the character 0, whereas my use of the select
attribute has the data type of number, which is what I think you are
trying to use.
I hope this helps.
. . . . . . Ken
At 2011-01-30 15:05 -0700, Karl Stubsjoen wrote:
I'm perplexed. I have a template match routine and param value that
is not receiving the param value passed. I am passing the param value
like this:
<xsl:with-param name="group-value" select="number(16)"/>
The param is defined in the template match like this:
<xsl:param name="group-value">0</xsl:param>
The value is always:
type:ABC
value: "0"
(According to Oxygen)
I have a simple XML sample and the number param value is passed fine.
In my real example (working xml/xsl templates) it is not passed. The
stylsheet is quite involved (over 30,000 lines). I am stepping
through the code (I can provide screen shots) and the param value
default to the >0< "0" value. Any ideas? I have stepped through this
a 1/2 dozen times now!
Karl..
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Karl Stubsjoen
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(602) 845-0006
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