===Plain text===
Hello All,
Following is the test xml I am working on
<Description>
<core
resource="http://xyz.com/93034B4E-5686-4FF5-9EAD-F603F42B897F/viewas/xml"/>
<core
resource="http://xyz.com/E4E0EF48-030F-4ACE-B15E-E923AC582A6B/viewas/xml"/>
<core
resource="http://xyz.com/9808A0E2-5678-435F-8C89-5B7C8C27E380/viewas/xml"/>
<core
resource="http://xyz.com/80E137ED-E8CC-4B14-AC47-E437D8E91BBA/viewas/xml"/>
<core
resource="http://xyz.com/97337AAC-81CF-4DD8-9C8F-B06744B13753/viewas/xml"/>
<core
resource="http://xyz.com/114F7C46-C207-49BE-96D1-B5E4314342B9/viewas/xml"/>
<Description>
The value of resource attribute is a link to the XML
document.
I need to write an XSLT which creates 6 different output
file (as there are 6 <core>), and every output file should have their
respective XML.
=========
This is the test.xslt I wrote
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:fn="http://www.w3.org/2005/xpath-functions">
<xsl:output
method="xml" version="1.0" encoding="UTF-8"
indent="yes" name="xml"/>
<xsl:template
match="/">
<xsl:for-each
select="//core">
<xsl:variable
name="filename"
select="concat('output1/',substring(substring-after(@*:resource,'xyz.com/'),1,5),'.xml')"/>
<xsl:value-of
select="$filename"/>
<!--
Creating -->
<xsl:result-document
href="{$filename}" format="xml">
<xsl:value-of
select="@*:resource"/>
</xsl:result-document>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
===========
I was able to get 6 different xml files, but they were
having the value of the respective resource attribute, not the whole XML.
Output
========
<?xml version="1.0"
encoding="UTF-8"?>
http://xyz.com/93034B4E-5686-4FF5-9EAD-F603F42B897F/viewas/xml
Required output is to get the whole XML, which appears
when the link is clicked/navigated.
Is there any way I can achieve this using XSLT.
Thanks,
Shashank Jain
----------------------------------------
From: shashankjain(_at_)live(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Date: Wed, 13 Apr 2011 12:15:39 -0500
Subject: [xsl] Access XML from the URL and put in different file
Hello All,
Following is the test xml I am working on
The value of resource attribute is a link to the XML document. I need to
write an XSLT which creates 6 different output file (as there are 6 ), and
every output file should have their respective XML.
=========This is the test.xslt I wrote ===========I was able to get
6 different xml files, but they were having the value of the respective
resource attribute, not the whole XML.
Output========http://xyz.com/93034B4E-5686-4FF5-9EAD-F603F42B897F/viewas/xml
Required output is to get the whole XML, which appears when the link is
clicked/navigated.
Is there any way I can achieve this using XSLT.
Thanks,Shashank Jain
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