Hello All,
Following is the test xml I am working on
<Description> <core
resource="http://xyz.com/93034B4E-5686-4FF5-9EAD-F603F42B897F/viewas/xml"/>
<core
resource="http://xyz.com/E4E0EF48-030F-4ACE-B15E-E923AC582A6B/viewas/xml"/>
<core
resource="http://xyz.com/9808A0E2-5678-435F-8C89-5B7C8C27E380/viewas/xml"/>
<core
resource="http://xyz.com/80E137ED-E8CC-4B14-AC47-E437D8E91BBA/viewas/xml"/>
<core
resource="http://xyz.com/97337AAC-81CF-4DD8-9C8F-B06744B13753/viewas/xml"/>
<core
resource="http://xyz.com/114F7C46-C207-49BE-96D1-B5E4314342B9/viewas/xml"/><Description>
The value of resource attribute is a link to the XML document. I need to write
an XSLT which creates 6 different output file (as there are 6 <core>), and
every output file should have their respective XML.
=========This is the test.xslt I wrote<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xs="http://www.w3.org/2001/XMLSchema";
xmlns:fn="http://www.w3.org/2005/xpath-functions";> <xsl:output method="xml"
version="1.0" encoding="UTF-8" indent="yes" name="xml"/> <xsl:template
match="/"> <xsl:for-each select="//core">
<xsl:variable name="filename"
select="concat('output1/',substring(substring-after(@*:resource,'xyz.com/'),1,5),'.xml')"/>
<xsl:value-of select="$filename"/>
<!-- Creating --> <xsl:result-document href="{$filename}"
format="xml"> <xsl:value-of select="@*:resource"/>
</xsl:result-document> </xsl:for-each>
</xsl:template></xsl:stylesheet>===========I was able to get 6 different xml
files, but they were having the value of the respective resource attribute, not
the whole XML.
Output========<?xml version="1.0"
encoding="UTF-8"?>http://xyz.com/93034B4E-5686-4FF5-9EAD-F603F42B897F/viewas/xml
Required output is to get the whole XML, which appears when the link is
clicked/navigated.
Is there any way I can achieve this using XSLT.
Thanks,Shashank Jain
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