Hi Steve,
Probably something like following might work (not tested),
<xsl:variable name="posOfNode" as="xs:integer">
<xsl:for-each select="$nodelist">
<xsl:if test="is-same-node(., $mynode)">
<xsl:value-of select="position()"/>
</xsl:if>
</xsl:for-each>
</xsl:variable>
<xsl:variable name="result" select="$nodelist[$posOfNode - 1]"/>
I imagine, there may be a better way also to solve this problem.
On Fri, Apr 22, 2011 at 6:58 AM, Steve Fogel
<STEVE(_dot_)FOGEL(_at_)oracle(_dot_)com> wrote:
Hi, all...
Would appreciate a suggestion:
If:
- I have a node set in the variable $nodelist
- and I have a single node in the variable $mynode
- and the node in $mynode is a member of $nodelist
then in XSLT 2.0, how do I set a variable to contain the node that is
previous to $mynode in $nodelist?
For simplicity and a quick answer, you can assume that all nodes in $nodelist
are siblings, but in reality, $nodelist contains <topicref>s from a DITA map,
so the previous node could be a sibling, a parent, or the child of the
previous sibling.
Many thanks
Steve Fogel
Information Architect, Oracle Database
Oracle Corporation
--
Regards,
Mukul Gandhi
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