Hi Michael,
Although the snippet was showing a xquery, the very question itself was not so
much xquery related. I would rather say it was related to Xpath functions.
I could have asked the same question in another format and the answer would
have been the same:
<xsl:param name="uri" as="xs:anyURI"/>
<xsl:template match="/">
<xsl:copy-of select="doc($uri)/Content"/>
</xsl:template>
For which it would have been easier to do
<xsl:param name="uri" as="xs:string"/>
<xsl:template match="/">
<xsl:copy-of select=" doc(xs:anyURI($uri))/Content"/>
</xsl:template>
Bottom line.. The example might be inapprioriate but I may assume that
questions related Xpath functions (http://www.w3.org/TR/xpath-functions/) are
welcome to this list as well?
Robby
-----Original Message-----
From: Michael Kay [mailto:mike(_at_)saxonica(_dot_)com]
Sent: Wednesday, July 06, 2011 5:04 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] question regarding setting anyURI from java
On 06/07/2011 10:50, Robby Pelssers wrote:
Hi all,
I am trying to get the below query working but i have trouble setting the
variable from Java. If I use java.net.URI i get following
exception:javax.xml.xquery.XQException: Java object cannot be converted to an
XQuery value
-----------------------------------------
declare variable $uri as xs:anyURI external;
doc($uri)
-----------------------------------------
Can someone shed some light on this?
This is XQuery, so it's off-topic for this list. Ask again on talk @
x-query.com, or on StackOverflow - and tell us which XQuery product you
are using, and what calls you are making on the XQJ API.
Michael Kay
Saxonica
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