Re: [xsl] compare two nodes (the child elements, not the string values)

Am 06.07.2011 um 20:54 schrieb Wolfhart Totschnig:

> I have a seemingly simple xslt problem to which I cannot find the solution. I 
> want to test whether the context node, which is an <author> element with the 
> form (first?, middle?, last), is equal to one of a set of <person> elements. 
> By "equal" I mean having the same child elements and values of these 
> elements. At first, I thought it would be as easy as
>
> test="path/person = ."
>
> But then I realized that the "=" operator compares the string values of the 
> nodes
Wolfhart,

How about this (not very cool):

test="concat(path/person/first, '|', path/person/first, '|', path/person/first) 
    = concat(first, '|', middle, '|', last)"

- Michael Müller-Hillebrand


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