Re: [xsl] compare two nodes (the child elements, not the string values)

Can't you use keys? You could setup a key based on the concatenated
values and see if there is a person for that key.

Michel

On Thu, Jul 7, 2011 at 6:55 AM, Wolfhart Totschnig
<wolfhart(_at_)totschnig(_dot_)org> wrote:
> Hi,
>
> Thanks to all who responded!
>
> For my particular case, I found a less complicated solution than Wendell's,
> but it's a particular solution, not a general one:
>
> <xsl:variable name="last" select="last"/>
> <xsl:if test="path/person/last=last and (not(first) or
> path/person[last=$last]/first=first) and (not(middle) or
> path/person[last=$last]/middle=middle)">
>
> I am amazed that there is no simple general solution for this kind of
> problem in XSLT 1.0. I thought I must be overlooking something obvious. XSLT
> 2.0 indeed makes life easier!
>
> Thanks again,
> Wolfhart
>
>
> Wendell Piez wrote:
> > Hi,
> >
> > A generalization of Michael's suggestion is to use a mode in which each
> > element is processed to write strings, and then compare the strings.
> >
> > So:
> >
> > <xsl:variable name="author-string">
> >  <!-- generating an RTF containing a string -->
> >  <xsl:apply-templates select="$author" mode="string"/>
> > </xsl:variable>
> > <xsl:variable name="person-string">
> >  <!-- again -->
> >  <xsl:apply-templates select="$person" mode="string"/>
> > </xsl:variable>
> > <xsl:if test="$author-string = $person-string"> ...
> >
> > You can then manage how each string is generated, for purposes of
> > comparison, using templates matching in the mode. (You will find you need to
> > do some of this in order, for example, to normalize whitespace.)
> >
> > To compare an author to more than one person, wrap your calls in a
> > template that writes a result string you can test for. So:
> >
> > <xsl:template name="compare-person">
> >  <xsl:param name="author" select="/.."/>
> >  <xsl:param name="person" select="."/>
> >  <xsl:variable name="author-string">
> >    <xsl:apply-templates select="$author" mode="string"/>
> >  </xsl:variable>
> >  <xsl:variable name="person-string">
> >    <xsl:apply-templates select="$person" mode="string"/>
> >  </xsl:variable>
> >  <xsl:if test="$author-string = $person-string"> TRUE </xsl:if>
> > </xsl:template>
> >
> > Then:
> >
> > <xsl:template match="author">
> >  <xsl:variable name="author" select="."/>
> >  <xsl:variable name="compare-result">
> >    <xsl:for-each select="$persons">
> >      <!-- generating an RTF containing a string,
> >           possibly including 'TRUE' -->
> >      <xsl:call-template name="compare-person">
> >        <xsl:with-param name="author" select="$author">
> >      </xsl:call-template>
> >    <xsl:for-each>
> >  </xsl:variable>
> >  <xsl:if test="contains($compare-result,'TRUE')"> ...
> >
> > Note this doesn't tell you which of your persons is (are) the same as your
> > author. For that you have to work harder (there are ways).
> >
> > This little exercise in XSLT 1.0 may well convince you that life is easier
> > under XSLT 2.0.
> >
> > Cheers,
> > Wendell
> >
> > On 7/6/2011 4:22 PM, Michael Müller-Hillebrand wrote:
> > > Am 06.07.2011 um 20:54 schrieb Wolfhart Totschnig:
> > >
> > > > I have a seemingly simple xslt problem to which I cannot find the
> > > > solution. I want to test whether the context node, which is an<author>
> > > >  element with the form (first?, middle?, last), is equal to one of a set
> > > > of<person>  elements. By "equal" I mean having the same child elements and
> > > > values of these elements. At first, I thought it would be as easy as
> > > >
> > > > test="path/person = ."
> > > >
> > > > But then I realized that the "=" operator compares the string values of
> > > > the nodes
> > > Wolfhart,
> > >
> > > How about this (not very cool):
> > >
> > > test="concat(path/person/first, '|', path/person/first, '|',
> > > path/person/first)
> > >     = concat(first, '|', middle, '|', last)"
> > >
> > > - Michael Müller-Hillebrand
>
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