Sorry I didn't specify it correctly. I need to extract just the
payload value. So output would like something like:
output 1 (no payload value):
<api>
<name>get</name>
<payload></payload>
</api>
output 2 (just the payload value):
assaddddd
On Mon, Aug 22, 2011 at 1:15 PM, Mohit Anchlia
<mohitanchlia(_at_)gmail(_dot_)com> wrote:
On Sun, Aug 21, 2011 at 10:46 AM, Martin Honnen
<Martin(_dot_)Honnen(_at_)gmx(_dot_)de> wrote:
Mohit Anchlia wrote:
I have payload something like
<api>
<name>get</name>
<payload>assaddddd</payload>
</api>
We have got a requiement to save all incoming request except the
"payload" on the wire. Also, one of the option I think is to use XSL
transformation to strip the payloads. I need some suggestion on if
it's the good way and also how can I possibly do it using xslt.
Well if you want to strip the payload element(s) then do
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="payload"/>
In the same transformation is it possible to output 2 separate pieces:
1) Payload
2) Everything but payload
We need to persist them but separately
--
Martin Honnen --- MVP Data Platform Development
http://msmvps.com/blogs/martin_honnen/
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail:
<mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--