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Re: [xsl] Stripping payloads

2011-08-22 15:20:29
Sorry I didn't specify it correctly. I need to extract just the
payload value. So output would like something like:

output 1 (no payload value):
 <api>
    <name>get</name>
    <payload></payload>
 </api>

output 2 (just the payload value):

assaddddd

On Mon, Aug 22, 2011 at 1:15 PM, Mohit Anchlia 
<mohitanchlia(_at_)gmail(_dot_)com> wrote:
On Sun, Aug 21, 2011 at 10:46 AM, Martin Honnen 
<Martin(_dot_)Honnen(_at_)gmx(_dot_)de> wrote:
Mohit Anchlia wrote:

I have payload something like

<api>
   <name>get</name>
   <payload>assaddddd</payload>
</api>

We have got a requiement to save all incoming request except the
"payload" on the wire. Also, one of the option I think is to use XSL
transformation to strip the payloads. I need some suggestion on if
it's the good way and also how can I possibly do it using xslt.

Well if you want to strip the payload element(s) then do

<xsl:template match="@* | node()">
 <xsl:copy>
   <xsl:apply-templates select="@* | node()"/>
 </xsl:copy>
</xsl:template>

<xsl:template match="payload"/>

In the same transformation is it possible to output 2 separate pieces:

1) Payload
2) Everything but payload

We need to persist them but separately





--

       Martin Honnen --- MVP Data Platform Development
       http://msmvps.com/blogs/martin_honnen/

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