On 22/08/2011 22:57, Mohit Anchlia wrote:
I am wondering if it's even possible to get 2 separate output from single parse?
I was able to get output 1 by doing something like:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="payload">
<payload></payload>
</xsl:template>
</xsl:stylesheet>
On Mon, Aug 22, 2011 at 1:20 PM, Mohit
Anchlia<mohitanchlia(_at_)gmail(_dot_)com> wrote:
Sorry I didn't specify it correctly. I need to extract just the
payload value. So output would like something like:
output 1 (no payload value):
<api>
<name>get</name>
<payload></payload>
</api>
output 2 (just the payload value):
assaddddd
On Mon, Aug 22, 2011 at 1:15 PM, Mohit
Anchlia<mohitanchlia(_at_)gmail(_dot_)com> wrote:
On Sun, Aug 21, 2011 at 10:46 AM, Martin
Honnen<Martin(_dot_)Honnen(_at_)gmx(_dot_)de> wrote:
Mohit Anchlia wrote:
I have payload something like
<api>
<name>get</name>
<payload>assaddddd</payload>
</api>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="api">
<xsl:result-document href="a.xml">
<api>
<xsl:copy-of select="* except payload"/>
</api>
<xsl:result-document>
<xsl:result-document href="b.xml">
<api>
<xsl:copy-of select="payload/node()"/>
</api>
<xsl:result-document>
<xsl:template>
</xsl:stylesheet>
If you are stuck with xslt version 1 there is no standard way to do two
output documents, but many systems have extension functions to do that,
eg saxon6 had saxon:document.
David
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