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Re: [xsl] anyURI problem

2011-08-26 03:42:15
On 26 August 2011 09:33, Jan Pour <xpouj04(_at_)gmail(_dot_)com> wrote:
Hi,

I tried both ways of how to cope with [Content_Types].xml
file in xsl:result-document href attribute:

Try using the iri-to-uri() function to turn this into a valid URI.

Saxon is fussier than some other products about insisting that URIs are
valid.

Michael Kay
Saxonica

That didn’t work for me, but
href="{encode-for-uri('[Content_Types].xml')}"
did.

Or verbose
href="%5bContent_Types%5d.xml"

Gerrit

in Saxon 8 I was able to generate such file, but with versions 9.*
I was not successful. With encode-for-uri() function 0-length file was
generated with following error message:

java.net.URISyntaxException: Illegal character in path at index 21:
file:///C:/xslt/test/[Content_Types].xml

I tried Saxon versions: 9, 9.1 and 9.3he
Is there any other solution?

If you don't post the code it's hard to see where you are going wrong....

Guessing, you've probably wrapped the whole path in encode-for-uri,
rather than just the filename:

href="{concat('file:///C:/xslt/test/', encode-for-uri('[Content_Types.xml'))}"



-- 
Andrew Welch
http://andrewjwelch.com

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