Sorry, but it don't.
I still get the no output error message.
Roelof
----------------------------------------
From: Robby(_dot_)Pelssers(_at_)nxp(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Date: Tue, 22 Nov 2011 10:21:56 +0100
Subject: RE: [xsl] Can grouping here the solution ?
This should get the job done.. I forgot to adjust the matching template to
<xsl:template match="artikel-details">
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN"
doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd";
omit-xml-declaration="yes" encoding="UTF-8" indent="yes" />
<xsl:param name="pageNumber"/>
<xsl:template match="/">
<xsl:apply-templates select="artikel-details "/>
</xsl:template>
<xsl:template match="artikel-details">
<xsl:for-each-group select="entry" group-by="page">
<xsl:if test="current-grouping-key() eq $pageNumber">
<xsl:apply-templates select="current-group()"/>
</xsl:if>
</xsl:for-each-group>
</xsl:template>
<xsl:template match="entry">
<h1><xsl:value-of select="titel"/></h1><br />
<xsl:value-of select="datum" /><br />
<xsl:value-of select="tekst" />
</xsl:template>
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--