thanks, but It is a change in the specification.
Here is the sample:
Sample Input :12,345
output:
After comma ever 8 digits
And whole string should be 14 digits:
Sample out: 00012,34500000
Best regards
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Von: G. Ken Holman <gkholman(_at_)CraneSoftwrights(_dot_)com>
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Cc:
Gesendet: 16:56 Mittwoch, 4.Januar 2012
Betreff: Re: [xsl] format string with leading zeros
At 2012-01-04 15:46 +0000, henry human wrote:
Hi I have following scenario, the itemCode field must be 14 digits lang. I
try to ignore the last two decimals of the itemCode field if the itemCode is
more than 14 digits long (16 digits). And if the itemCode has less than 14,
fill field with leading zeros so that the itemCodeCode is still 14 digits
long. Input Example(1): itemCode : 0.0123456789 output itemCode:
000.0123456789 Input Example(2): itemCode : 0.01111123456789 output itemCode:
0.011111234567 Thanks you
Does the following help? It uses two steps to first trim and then pad the
input to produce the output.
. . . . . . . . . Ken
~/t/ftemp $ xslt2 henry.xsl henry.xsl
<?xml version="1.0" encoding="UTF-8"?>
000.0123456789
0.011111234567
~/t/ftemp $ cat henry.xsl
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:my="urn:X-Henry" exclude-result-prefixes="my"
version="2.0">
<xsl:template match="/">
<xsl:text>
</xsl:text>
<xsl:value-of select="my:trim('0.0123456789')"/>
<xsl:text>
</xsl:text>
<xsl:value-of select="my:trim('0.01111123456789')"/>
<xsl:text>
</xsl:text>
</xsl:template>
<xsl:function name="my:trim">
<xsl:param name="str"/>
<xsl:variable name="temp"
select="concat('00000000000000',substring($str,1,14))"/>
<xsl:sequence select="substring($temp,string-length($temp)-13)"/>
</xsl:function>
</xsl:stylesheet>
~/t/ftemp $
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