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Re: [xsl] Removing unwanted namespaces

2012-01-13 10:10:31
Hi,

I wasn't aware of this requirement. Then indeed we need one more
template for the root element, but it shall copy only those namespaces
which don't belong to the suppressed elements or their descendants:

<xsl:template match="/*">
   <xsl:element name="{name(.)}" namespace="{namespace-uri(.)}">
      <xsl:copy-of select="//*[
         not(ancestor-or-self::*[
            local-name()='abcdHeader' or local-name()='Context'
         ])]/namespace::*[.=namespace-uri(..)]"/>
      <xsl:apply-templates select="@*|node()"/>
   </xsl:element>
</xsl:template>

Cheers,
Markus

Wendell Piez wrote:
Hi again,

Yes, this will work, but I think Ram also said he wants all namespace 
declarations at the top. Since this logic effectively strips all 
namespace nodes except where they are needed, the declarations will only 
appear at the point (or points, within the tree hierarchy) of first use.

(I also don't like using "*[local-name()='x']" tests but I'm unwilling 
to say they're bad, exactly. It's just that there are usually more 
graceful ways. :-)

Cheers,
Wendell

On 1/11/2012 7:04 PM, Markus Abt wrote:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
version="1.0">

<xsl:template match="@*|node()" priority="-1">
    <xsl:copy>
       <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="*">
    <xsl:element name="{name(.)}" namespace="{namespace-uri(.)}">
       <xsl:apply-templates select="@*|node()"/>
    </xsl:element>
</xsl:template>

<xsl:template match="*[local-name()='abcdHeader']"/>
<xsl:template match="*[local-name()='Context']"/>

</xsl:stylesheet>


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