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Re: [xsl] how to achieve this ?

2012-01-23 01:35:51

Op 23 jan 2012, om 08:26 heeft Roelof Wobben het volgende geschreven:

Not knowing how the input looks like, i would say that:
<ul class="menu" id={concat('menu', @value)}>

should do it for you, its a short notation for xsl:value-of select
 

For a menu I have to take care that every <menu class> get a unique id.

I thought this would work : 

<xsl:template match="year">
<ul class="menu" id= "concat ('menu', @value)" >
   <li>
   <a href="#"> <xsl:value-of select="@value"/> </a>
     <ul class="acitem">
            <xsl:apply-templates select="month" />
     </ul>
    </li>
</ul>
</xsl:template>

But it don't work.

Do I have to use here <xsl:value-of> or is there a better way ?


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