Thanks,
It solved the id problem but the menu still don't work right.
It still don't work as as accordian menu. See http://test.tamarawobben.nl
Roelof
---------------------------------------- > From: bbosgoed(_at_)bkwi(_dot_)nl >
Date: Mon, 23 Jan 2012 08:35:36 +0100 > To:
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com > Subject: Re: [xsl] how to
achieve this ? > > > Op 23 jan 2012, om 08:26 heeft Roelof Wobben het volgende
geschreven: > > Not knowing how the input looks like, i would say that: > <ul
class="menu" id={concat('menu', @value)}> > > should do it for you, its a short
notation for xsl:value-of select > > > > For a menu I have to take care that
every <menu class> get a unique id. > > > > I thought this would work : > > > >
<xsl:template match="year"> > > <ul class="menu" id= "concat ('menu', @value)"
<li> > > <a href="#"> <xsl:value-of select="@value"/> </a> > > <ul
class="acitem"> > > <xsl:apply-templates select="month" /> > > </ul> > > </li>
</ul> > > </xsl:template> > > > > But it don't work. > > > > Do I have to
use here <xsl:value-of> or is there a better way ? > > >
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