Am Sat, 10 Mar 2012 16:00:47 +0530 schrieb Mukul Gandhi:
Hi Mukul,
thanks for that hints! I never used that call-templates before. After
some experiments I got it somehow running in my xsl:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template name="printStateTree"
xmlns:dotml="http://www.martin-loetzsch.de/DOTML";>
<xsl:param name="curState"/>
<xsl:element name="node">
<xsl:attribute name="id"><xsl:value-of select="$curState/@name"/>
</xsl:attribute>
<xsl:attribute name="label"><xsl:value-of select="$curState/@name"/>
</xsl:attribute>
<xsl:attribute name="fontname">Arial</xsl:attribute>
<xsl:attribute name="fontsize">9</xsl:attribute>
<xsl:for-each select="//state[@parent = $curState/@name]">
<xsl:call-template name="printStateTree">
<xsl:with-param name="curState" select="."/>
</xsl:call-template>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template match="/">
<dotml:graph file-name="stateval"
xmlns:dotml="http://www.martin-loetzsch.de/DOTML";
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
xsi:schemaLocation="http://www.martin-loetzsch.de/DotML
../dotml-1.3/dotml-1.3.xsd" label="stateval" fontcolor="#0000A0"
fontname="Arial Bold" margin="0.2,0.1" ranksep="0.2" nodesep="0.5"
bgcolor="#F0F0FF" fontsize="13" style="dashed">
<xsl:for-each select="stateval/states">
<xsl:call-template name="printStateTree">
<xsl:with-param name="curState" select="state[not(@parent)]"/>
</xsl:call-template>
</xsl:for-each>
<xsl:for-each select="stateval/transitions/transition">
<dotml:edge>
<xsl:attribute name="from"><xsl:value-of select="@from"/>
</xsl:attribute>
<xsl:attribute name="to"><xsl:value-of select="@to"/>
</xsl:attribute>
<xsl:attribute name="label"><xsl:value-of select="@event"/>
</xsl:attribute>
<xsl:attribute name="fontname">Arial</xsl:attribute>
<xsl:attribute name="fontsize">7</xsl:attribute>
</dotml:edge>
</xsl:for-each>
</dotml:graph>
</xsl:template>
<xsl:template match="*|text()|@*">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
But the output is still not as I need it:
<?xml version="1.0"?>
<dotml:graph xmlns:dotml="http://www.martin-loetzsch.de/DOTML";
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"; file-name="stateval"
xsi:schemaLocation="http://www.martin-loetzsch.de/DotML
../dotml-1.3/dotml-1.3.xsd" label="stateval" fontcolor="#0000A0"
fontname="Arial Bold" margin="0.2,0.1" ranksep="0.2" nodesep="0.5"
bgcolor="#F0F0FF" fontsize="13" style="dashed">
<node id="Root" label="Root" fontname="Arial" fontsize="9">
<node id="Initial" label="Initial" fontname="Arial" fontsize="9" />
<node id="Final" label="Final" fontname="Arial" fontsize="9" />
<node id="Main" label="Main" fontname="Arial" fontsize="9" />
<node id="Browser" label="Browser" fontname="Arial" fontsize="9" />
<node id="Settings" label="Settings" fontname="Arial" fontsize="9" />
<node id="EMail_Compound" label="EMail_Compound" fontname="Arial"
fontsize="9">
<node id="EMail_Compound_Initial" label="EMail_Compound_Initial"
fontname="Arial" fontsize="9" />
<node id="EMail_Compound_History" label="EMail_Compound_History"
fontname="Arial" fontsize="9" />
<node id="EMail_Read" label="EMail_Read" fontname="Arial"
fontsize="9" />
<node id="EMail_Compose" label="EMail_Compose" fontname="Arial"
fontsize="9" />
</node>
</node>
<dotml:edge from="Initial" to="Main" label="" fontname="Arial" fontsize="7"
/>
<dotml:edge from="Root" to="Final" label="EXIT" fontname="Arial"
fontsize="7" />
<dotml:edge from="Root" to="Main" label="MAIN" fontname="Arial"
fontsize="7" />
<dotml:edge from="Root" to="Browser" label="BROWSER" fontname="Arial"
fontsize="7" />
<dotml:edge from="Root" to="Settings" label="SETTINGS" fontname="Arial"
fontsize="7" />
<dotml:edge from="Root" to="EMail_Compound" label="EMAIL" fontname="Arial"
fontsize="7" />
<dotml:edge from="EMail_Compound" to="EMail_Compound_Initial" label=""
fontname="Arial" fontsize="7" />
<dotml:edge from="EMail_Compound_Initial" to="EMail_Compound_History"
label="" fontname="Arial" fontsize="7" />
<dotml:edge from="EMail_Compound_History" to="EMail_Read" label=""
fontname="Arial" fontsize="7" />
<dotml:edge from="EMail_Compound" to="EMail_Compose" label="EMAIL_COMPOSE"
fontname="Arial" fontsize="7" />
<dotml:edge from="EMail_Compound" to="EMail_Read" label="EMAIL_READ"
fontname="Arial" fontsize="7" />
</dotml:graph>
It has now correct transformation into a parent relation, but dotml needs
format like this:
<record >
<node id="10" label="left"/>
<node id="11" label="middle"/>
<node id="12" label="right"/>
</record>
<record >
<node id="20" label="one"/>
<node id="21" label="two"/>
</record>
I tried to learn more about xsl by reading w3schools docu, but I wasn't able to
get exact that result. So I like to have this:
Could you maybe give me please another hint?
regards
Andreas
Hi Andreas,
May I propose a solution, which may be a start.
I guess, your area of interest for transformation is following XML
fragment (which is the only place, where I can see the "parent"
attribute),
<states>
<state name="root" type="CompoundState"/>
<state name="a" type="SimpleState" parent="root"/>
<state name="choose" type="DecisionState" parent="root"/>
<state name="b" type="SimpleState" parent="root"/>
<state name="c" type="SimpleState" parent="root"/>
</states>
So here's my proposal for this transformation,
<!-- starting point -->
<xsl:call-template name="printStateTree">
<xsl:with-param name="curState" select="state[not(@parent)]"/>
</xsl:call-template>
<xsl:template name="printStateTree">
<xsl:param name="curState"/>
<xsl:element name="{$curState/@name}"/>
<xsl:for-each select="//state[@parent = $curState/@name]">
<xsl:call-template name="printStateTree">
<xsl:with-param name="curState" select="."/>
</xsl:call-template>
</xsl:for-each>
</xsl:element>
</xsl:template>
This is not tested. The output format of this XSLT fragment is
unrelated to your actual output (and it is not optimized -- since it
has the expression //state, and output probably not normalized to be a
good tree format). This XSLT fragment only intends to demonstrate the
technique that I had in mind.
Just some food for thought :)
On Sat, Mar 10, 2012 at 1:44 PM, Andreas Volz <lists(_at_)brachttal(_dot_)net>
wrote:
Am Sat, 3 Mar 2012 11:21:09 +0100 schrieb Andreas Volz:
Hello,
I've a list with a flat tree that has a parent attribute to save
child/father relations.
http://stateval.googlecode.com/svn/trunk/stateval/test/features/ft2.smxml
I just like to transform this state machine graph in DotML format
to display it as SVG:
http://martin-loetzsch.de/DOTML/record.html
I've yet a somehow working version:
http://stateval.googlecode.com/svn/trunk/stateval/doc/graph_gen/stateval_dotml.xsl
But it has only a flat list and shows transitions between them. I
would like to handle CompoundStates as records in DotML. So I need
some transformation from my flat tree into that hierarchical tree
from DotML record.
I've no idea how to do this in xsl. I'm using xsltproc in Ubuntu
11.10:
xsltproc --version
Using libxml 20708, libxslt 10126 and libexslt 815
xsltproc was compiled against libxml 20708, libxslt 10126 and
libexslt 815 libxslt 10126 was compiled against libxml 20708
libexslt 815 was compiled against libxml 20708
As fas as I know it supports only XSLT 1.0.
Could you help me?
No hints? Did I ask in a wrong way? Or isn't this possible?
regards
Andreas
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Technical Blog <http://andreasvolz.wordpress.com/>
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Regards,
Mukul Gandhi
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