Thanks, it seems that still is somethin wrong in your statement. I get now the
correct Taxtotal (the first which has an element Amount) but it is
the WHOLE Taxtotal and not only the Amount!
Even if try this I get still the whole taxtotal:
select="TaxTotal[child::Amount[1]][1]"
----- Ursprüngliche Message -----
Von: Michele R Combs <mrrothen(_at_)syr(_dot_)edu>
An: "'xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com'"
<xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
CC:
Gesendet: 19:28 Donnerstag, 10.Mai 2012
Betreff: RE: [xsl] Get the first Array element
Sorry, extra closing quotes there:
select="TaxTotal[child::Amount][1]"
Michele
-----Original Message-----
From: Michele R Combs [mailto:mrrothen(_at_)syr(_dot_)edu]
Sent: Thursday, May 10, 2012 1:28 PM
To: 'xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com'
Subject: RE: [xsl] Get the first Array element
In your code example there is only ONE occurrence of TaxTotal/Amount -- in that
case, select="TaxTotal/Amount" will work.
If there are multiple TaxTotal/Amounts and you only want the first one, then I
think select="TaxTotal[child::Amount][1]"" would do it.
Michele
-----Original Message-----
From: henry human [mailto:henry_human(_at_)yahoo(_dot_)de]
Sent: Thursday, May 10, 2012 12:18 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Get the first Array element
Sorry it was a mistake in the posting:
Correction:
I will get the FIRST Taxtotal element which has the Amount element I tried it
with <xsl-value-of select="TaxTotal[1]/Amount"/> But it does not work as
expected because I get the other Taxtotal (the first one) which has not the
element 'Amount'
Here is my XML data:
<elements>
....
<TaxTotal>
<otherAmount>22.00</otherAmount>
</TaxTotal>
.......
<TaxTotal>
<otherAmount>90.00</otherAmount>
</TaxTotal>
<TaxTotal>
.....
<Amount>44.00</Amount>
</TaxSubtotal>
</TaxTotal>
<TaxTotal>
.....
<Amount>10.00</Amount>
</TaxSubtotal>
</TaxTotal>
......
</elements>
I hope i am now more cleare
??
----- Ursprüngliche Message -----
Von: henry human <henry_human(_at_)yahoo(_dot_)de>
An: "xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com"
<xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
CC:
Gesendet: 17:59 Donnerstag, 10.Mai 2012
Betreff: Re: [xsl] Get the first Array element
Sorry it was a mistake in the posting:
Correction:
I will get the FIRST Taxtotal element which has the Amount element I tried it
with <xsl-value-of select="TaxTotal[1]/RoundingAmount"/>
But it does not work as expected because I get the other Taxtotal (the first
one) which has not the element 'Amount'
Here is my XML data:
<elements>
....
<TaxTotal>
<otherAmount>22.00</otherAmount>
</TaxTotal>
.......
<TaxTotal>
<otherAmount>90.00</otherAmount>
</TaxTotal>
<TaxTotal>
.....
<Amount>44.00</Amount>
</TaxSubtotal>
</TaxTotal>
<TaxTotal>
.....
<Amount>10.00</Amount>
</TaxSubtotal>
</TaxTotal>
......
</elements>
I hope i am now more cleare
??
----- Ursprüngliche Message -----
Von: Dimitre Novatchev <dnovatchev(_at_)gmail(_dot_)com>
An: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
CC:
Gesendet: 17:49 Donnerstag, 10.Mai 2012
Betreff: Re: [xsl] Get the first Array element
Unless you clearly define the problem, don't expect any useful response -- we
are not supernaturals and only have limited guessing power.
Cheers,
Dimitre
On Thu, May 10, 2012 at 7:11 AM, henry human <henry_human(_at_)yahoo(_dot_)de>
wrote:
Hello
<elements>
....
<TaxTotal>
<otherAmount>22.00</otherAmount>
</TaxTotal>
.......
<TaxTotal>
<otherAmount>90.00</otherAmount>
</TaxTotal>
<TaxTotal>
.....
<Amount>44.00</Amount>
</TaxSubtotal>
</TaxTotal>
<TaxTotal>
.....
<Amount>10.00</Amount>
</TaxSubtotal>
</TaxTotal>
......
</elements>
---------------------
Ever I will get the FIRST Taxtotal because this has the Amount I tried
:cac:TaxTotal[1]/cbc:RoundingAmount
Butr It is wrong!
??
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Cheers,
Dimitre Novatchev
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To avoid situations in which you might make mistakes may be the biggest mistake
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