I guess you mean with " If I have it in this way in the otherwise.."
that you refer to your previous code.
Well again, the first test fails as it tests for a <space> value, not
an empty value. Then within the first otherwise it tests for the value
to be positive (which also fails) and after that you try to format the
not-found-Amount to something which results to NaN in the nested
otherwise. You might try and add attributes (numbers p.e. ) to the
totals/amount and see which ones go where in the (unnecessarirly
nested) choose.
Michel
On Fri, May 11, 2012 at 1:24 PM, henry human <henry_human(_at_)yahoo(_dot_)de>
wrote:
If I have it in this way in the otherwise part I get for that Taxtotal which
HAS NO Amount still a result
(<amount>00000000000000</amount>)
Therfore I did :
<xsl:otherwise></xsl:otherwise>
The solution works fine for me, thnak you guys!
But I think still this statement : <xsl:when
test="cac:TaxTotal[child::cbc:Amount][1]/cbc:Amount
does not query ONLY the taxtotal elemnets which HAS AN amount but the other
taxtotals too?
Kind regards
hny
----- Ursprüngliche Message -----
Von: Michel Hendriksen <michel(_dot_)hendriksen(_at_)42(_dot_)nl>
An: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
CC:
Gesendet: 12:27 Freitag, 11.Mai 2012
Betreff: Re: [xsl] Get the first Array element
First test had a space it seems, so never matched
So something like: (second part not needed I guess, test might better)
<xsl:choose>
<xsl:when test="cac:TaxTotal[child::cbc:Amount][1]/cbc:Amount >= 0">
<xsl:value-of
select="format-number(floor(cac:TaxTotal[child::cbc:Amount][1]/cbc:Amount),'+0000000000000;-0000000000000')
"/>
</xsl:when>
<xsl:when test="cac:TaxTotal[child::cbc:Amount][1]/cbc:Amount < 0">
<xsl:value-of
select="format-number(floor(cac:TaxTotal[child::cbc:Amount][1]/cbc:Amount),'+0000000000000;-0000000000000')
"/>
</xsl:when>
<xsl:otherwise>00000000000000</xsl:otherwise>
</xsl:choose>
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