On Mon, Oct 29, 2012 at 2:50 PM, Costello, Roger L.
<costello(_at_)mitre(_dot_)org> wrote:
Hi Folks,
I would like to fix one argument of the min() function to 2 and leave the
other argument undefined, thus producing a partially applied function. Then,
I would like to give the partially applied function a value. Here's what I
tried:
let $min2 := min((?,2))
return $min2(3)
I get this error: Unexpected token "?" in path expression
Min has a single argument, which is a sequence. Therefore:
let $min2 := min((?,2))
isn't correct, indeed, because the argument placeholder doesn't
substitute the whole and only argument of the function.
It seems to me the what you want is:
let $min2 := $compose(min#1, $makeSequence(?,2))
return
$min2(3)
where $compose should be similar to what was already discussed in this
list a few days ago and $makeSequence() must be essentially the same
as LISP's cons() funxction.
Cheers,
Dimitre
What's the correct way to accomplish this?
/Roger
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Cheers,
Dimitre Novatchev
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