xsl-list
[Top] [All Lists]

Re: [xsl] An XPath expression which checks that no two websites have the same username

2012-11-05 04:54:50
Perhaps comparing the count of all @to values with the count of the
union of all @to values:

count(map/*/@to) eq count(union(map/*/@to))

which assumes, of course, that you don't have full identical duplicates.

-W


On 05/11/2012, Costello, Roger L. <costello(_at_)mitre(_dot_)org> wrote:
Hi Folks,

I need a good XPath expression which checks that no two websites have the
same username.

Here is a map between websites and usernames:

    <map>
        <singletonMap from="Amazon"                   to="BasketballKing" />
        <singletonMap from="Apple"                    to="RandomGamer" />
        <singletonMap from="Ebay"                     to="CornFoo" />
        <singletonMap from="Google"                   
to="LatenightRevolution" />
        <singletonMap from="Microsoft"                to="OldTrue" />
        <singletonMap from="VirginAtlantic"           to="TheSinger" />
    </map>

In that example no two websites have the same username.

I created an XPath expression which does the job, but I suspect there is a
simpler expression. Here is my attempt:

empty(for $i in map/*/@to return map/*[@to eq $i][2])

Would you provide a simpler (more efficient, more elegant) version please?

/Roger

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: 
<mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--



--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--

<Prev in Thread] Current Thread [Next in Thread>