xsl-list
[Top] [All Lists]

[xsl] Replacing \U+00A0

2013-08-23 14:23:32
Hi,

Having a problem replacing the following string in some XML, \U+00A0. It is 
appearing as is in the XML. Example: <p>This para\U+00A0contains.</p>

Using Saxon HE 9.5.0.1J.

Tried the following: 
<xsl:value-of select="if (contains(., '\U+00A0')) then replace(., '\U+00A0', ' 
') else ." />. Am able to find the string in question (using contains()) but am 
unable to replace it.

Any insight and help will be appreciated.

Thanks

Mario Madunic | Software Developer | AeroInfo Systems, A Boeing Company | 
mario(_dot_)madunic(_at_)aeroinfo(_dot_)com | #200-13575 Commerce Parkway | 
Richmond, BC, V6V 2L1, Canada | www.aeroinfo.com | www.boeing.com

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--


<Prev in Thread] Current Thread [Next in Thread>