xsl-list
[Top] [All Lists]

Re: [xsl] General rule for designing XPath expressions to return items in document order?

2014-01-08 05:54:36
On 08/01/2014 11:41, Costello, Roger L. wrote:
I'm confused. David says one thing, the spec says the opposite. Who's right?

Well me of course:-)

Or trust saxon:

<section>
        <section>
                <head>a</head>      <!-- A -->
        </section>
        <head>b</head>              <!-- B -->
</section>


<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:template match="/">
<xsl:sequence select="//section/head"/>
</xsl:template>
</xsl:stylesheet>





$ saxon9 sec.xml sec.xsl
<?xml version="1.0" encoding="UTF-8"?><head>a</head><head>b</head>


________________________________________________________________________
The Numerical Algorithms Group Ltd is a company registered in England
and Wales with company number 1249803. The registered office is:
Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom.

This e-mail has been scanned for all viruses by Star. The service is
powered by MessageLabs. ________________________________________________________________________

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--

<Prev in Thread] Current Thread [Next in Thread>