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Re: [xsl] Keys with duplicates should be simple

2014-01-31 15:22:38
Wendell,

In this particular instance the data is as simple as what is in the
OP. There is no other data. The thread originated from my erroneous
interpretation of the data structure, thinking it  was sorted because
I looked at the top half of the file, whereas it was  one sorted file
appended to another.

I'm happy to acknowledge mine may not be a universal solution but it
worked in the context I wanted it to. It is always nice when something
you ask becomes fodder for the finer XSLT brains in the group but I
have satisficed the problem and now regret interjecting into the
discussion between my elders and betters.

I'll be swinging by Rockville when next I am in town.

On Fri, Jan 31, 2014 at 8:51 PM, Wendell Piez 
<wapiez(_at_)wendellpiez(_dot_)com> wrote:
Ihe,

If you want to query a key (and who wouldn't), then you'll be
responsible for managing the scope of its use, assuming document-wide
scope unless you specifically say otherwise. It won't automatically
limit you to compare for 'duplicates' only within the parent, as does
the grouping solution or my XPath-based solution.

<xsl:apply-templates select="a/key('person-by-href', @href)[2]"/>

This one does not return third or fourth occurrences of 'duplicates'.
It only returns the second (if there is one).

If your key declaration is wrong all bets are off.

Cheers,
Wendell


On Fri, Jan 31, 2014 at 2:53 PM, Ihe Onwuka 
<ihe(_dot_)onwuka(_at_)gmail(_dot_)com> wrote:
  <xsl:import href="identity.xsl"/>
  <xsl:key name="person" match="a" use="@href"/>

  <xsl:template match="person">
    <duplicate>
      <xsl:apply-templates select="a[key('person',@href)[
2]]"/>
    </duplicate>
  </xsl:template>

If it's simple I should be able to describe it simply. Here goes.

Copy all a elements that have more than one entry in the key table
indexed by their value in the href attribute.

or maybe better.......

Create a key table using the href from each a element and copy all the
entries that occur more than once in it.



On Fri, Jan 31, 2014 at 7:34 PM, Dimitre Novatchev 
<dnovatchev(_at_)gmail(_dot_)com> wrote:
On Fri, Jan 31, 2014 at 11:28 AM, Ihe Onwuka 
<ihe(_dot_)onwuka(_at_)gmail(_dot_)com> wrote:
http://www.biglist.com/lists/lists.mulberrytech.com/xsl-list/archives/201211/msg00170.html

OP is using XSLT 2. OP only wants to find what things have duplicates.
Thats not a grouping problem, it's a problem that a certain variant of
for-each-group happens to solve but it's not the simplest way of
solving it.

 "Things that have duplicates" is exactly what we shouldn't be seeing
here -- to ambiguous (things, duplicates).

And "simple" is also very subjective. Do you mean "short", or what?
Does "simple" also mean efficient? Or should efficiency be of lower
priority?

As for "Things that have duplicates" -- see this -- just XPath 2 --
not even XSLT:


     http://stackoverflow.com/a/287360/36305



--
Cheers,
Dimitre Novatchev
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Wendell Piez | http://www.wendellpiez.com
XML | XSLT | electronic publishing
Eat Your Vegetables
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