As suspected it was possible to avoid grouping. See the predicate
tacked on to B/Date.
Thanks all.
<xsl:apply-templates select="A/Date | B/Date[not(A/Date/text() = text())]>
<xsl:sort select="." order="ascending"/>
</xsl:apply-templates>
On Wed, Mar 12, 2014 at 11:26 PM, Ihe Onwuka
<ihe(_dot_)onwuka(_at_)gmail(_dot_)com> wrote:
Yes that did occur but grouping syntax is not something I retain in
short term memory so am going to try and avoid that...... we'll see.
On Wed, Mar 12, 2014 at 10:09 PM, Wendell Piez
<wapiez(_at_)wendellpiez(_dot_)com> wrote:
Hi,
I hate to say it, but this is nicely handled as a grouping problem:
<xsl:for-each-group select="(A|B)/Date" group-by=".">
<xsl:apply-templates select=".'/> <!-- applies a template to the
first member of each group -->
<!-- select="current-group()[1]" to be more explicit -->
</xsl:for-each-group>
Many grouping problems are hidden in plain sight. :-)
Cheers, Wendell
On Wed, Mar 12, 2014 at 5:14 PM, Martin Holmes <mholmes(_at_)uvic(_dot_)ca>
wrote:
If the text content of the element is all you care about, you could do
something like this:
<xsl:variable name="distinctDates">
<xsl:for-each select="distinct-values(A/Date | B/Date)">
<xsl:sort/>
<Date><xsl:value-of select="."/></Date>
</xsl:for-each>
</xsl:variable>
<xsl:apply-templates select="$distinctDates/Date"/>
On 14-03-12 01:34 PM, Ihe Onwuka wrote:
I have Date elements coming from 2 different parents.
<A>
<Date>blah</Date>
</A>
<B>
<Date>blah</Date>
</B>
I am doing
<xsl:apply-templates select="A/Date | B/Date>
<xsl:sort select="." order="ascending"/>
</xsl:apply-templates>
and
<xsl:template match="Date">
etc
</xsl:template>
I have noticed that when A and B have a child element of the same date
the Date template gets fired on each occasion, whereas I only want it
fired once
I thought the union operator in the apply-templates would have the
effect of eliminating duplicates or aren't they duplicates if they
have the same content but come from different parents.
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