On 24/03/2014 14:08, Mario Madunic wrote:
(using XSLT 1)
Hi,
I would like to group numbers by if the following number is current number + 1
and so on.
Example:
<a>1</a>
<a>3</a>
<a>4</a>
<a>5</a>
<a>7</a>
<a>9</a>
<a>10</a>
<group><a>1</a></group>
<group><a>3 <a>4</a> <a>5</a></group>
<group><a>7</a></group>
<group><a>9</a> <a>10</a></group>
Any insight will be appreciated.
<x>
<a>1</a>
<a>3</a>
<a>4</a>
<a>5</a>
<a>7</a>
<a>9</a>
<a>10</a>
</x>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output indent="yes"/>
<xsl:template match="x">
<xsl:for-each-group group-starting-with="a[
not(preceding-sibling::a) or
not(number(.)=1+preceding-sibling::a[1])]" select="a">
<group>
<xsl:copy-of select="current-group()"/>
</group>
</xsl:for-each-group>
</xsl:template>
</xsl:stylesheet>
$ saxon9 numg.xml numg.xsl
<?xml version="1.0" encoding="UTF-8"?>
<group>
<a>1</a>
</group>
<group>
<a>3</a>
<a>4</a>
<a>5</a>
</group>
<group>
<a>7</a>
</group>
<group>
<a>9</a>
<a>10</a>
</group>
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